A) 3
B) 4
C) 5
D) 6
Correct Answer: B
Solution :
\[P{{\left( 1+\frac{20}{100} \right)}^{n}}>2P\] or \[{{\left( \frac{6}{5} \right)}^{n}}>2\] Now \[\left( \frac{6}{5}\times \frac{6}{5}\times \frac{6}{5}\times \frac{6}{5} \right)>2\] So \[n=4\] years
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