A) 102, 104, 15
B) 100,106,15
C) 104,100,17
D) 80,100,41
Correct Answer: A
Solution :
By hypothesis, \[\frac{A}{B+C}=\frac{6}{7}\] or \[7A=6(B+C)\] or \[7A-6B-6C=0\] ??(i) and \[\frac{B}{A+C}=\frac{8}{9}\] or \[9B=8(A+C)\] or \[8A-9B+8C=0\] ?..(ii) Solving equations (i) and (ii) by cross multiplication, we get \[\frac{A}{-48-54}=\frac{b}{-48-56}=\frac{C}{-63+48}\] or \[\frac{A}{-102}=\frac{B}{-104}=\frac{C}{-15}\] or \[\frac{A}{102}=\frac{B}{104}=\frac{C}{15}\] \[\therefore \]Sum of ratios \[=102+104+15=221\] Hence, A, B and C's shares are respectively \[Rs.102,\text{ }Rs.\text{ }104\] and \[Rs.\text{ }15\].You need to login to perform this action.
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