A) \[{{S}^{--}}\] is precipitate
B) No action takes places
C) Concentration of \[{{S}^{--}}\] decreases
D) Concentration of \[{{S}^{--}}\] increases
Correct Answer: D
Solution :
In IVth group the \[{{S}^{2-}}\]concentration increase when added the \[N{{H}_{4}}OH\,\,\,\,\text{because}\] \[N{{H}_{4}}OH\]⇌ \[NH_{4}^{+}+O{{H}^{-}}\] \[{{H}_{2}}S\] ⇌ \[2{{H}^{+}}+{{S}^{2-}}\] \[O{{H}^{-}}+{{H}^{+}}\] ⇌ \[{{H}_{2}}O\]. So that \[{{S}^{2-}}\]is increased.You need to login to perform this action.
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