A) \[{{10}^{-9}}\]
B) \[{{10}^{-8}}\]
C) \[{{10}^{-7}}\]
D) \[{{10}^{-6}}\]
Correct Answer: C
Solution :
\[BaS{{O}_{4}}\]⇌\[\underset{0.01\,\,\,\,}{\mathop{\underset{(S)\,\,\,\,\,\,\,}{\mathop{B{{a}^{++}}}}\,}}\,+\underset{5\,\,\,\,}{\mathop{\underset{(S)\,\,\,\,}{\mathop{SO_{4}^{-\,-}}}\,}}\,\] \[{{K}_{sp}}={{S}^{2}}=S\times S=0.01\times S\] \[{{S}_{(SO_{4}^{2-})}}=\frac{{{K}_{sp}}}{{{S}_{(B{{a}^{++}})}}}=\frac{1\times {{10}^{-9}}}{0.01}={{10}^{-7}}\]mole/litre
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