A) \[2.0\times {{10}^{-4}}\,mole/litre\]
B) \[12.0\times {{10}^{-3}}\,mole/litre\]
C) \[0.2\times {{10}^{-4}}\,mole/litre\]
D) \[2\times {{10}^{-3}}\,mole/litre\]
Correct Answer: A
Solution :
\[\underset{S}{\mathop{Ca{{F}_{2}}}}\,\]⇌\[\underset{S\,\,\,}{\mathop{C{{a}^{++}}}}\,+\underset{{{(2S)}^{2\,\,\,}}}{\mathop{2{{F}^{-}}}}\,\] \[{{K}_{sp}}=4{{S}^{3}}\] \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}\] \[=\sqrt[3]{\frac{3.2\times {{10}^{-11}}}{4}}\] \[=2\times {{10}^{-4}}\]m/l.
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