A) \[{{\sin }^{-1}}({{n}_{2}}/{{n}_{1}})\]
B) \[{{\sin }^{-1}}\sqrt{n_{1}^{2}-n_{2}^{2}}\]
C) \[\left[ {{\tan }^{-1}}\frac{{{n}_{2}}}{{{n}_{1}}} \right]\]
D) \[\left[ {{\tan }^{-1}}\frac{{{n}_{1}}}{{{n}_{2}}} \right]\]
Correct Answer: B
Solution :
Core of acceptance angle \[\theta ={{\sin }^{-1}}\sqrt{n_{1}^{2}-n_{2}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec