A) \[250\text{ }c{{m}^{2}}\]
B) \[300\text{ }c{{m}^{2}}\]
C) \[315\text{ }c{{m}^{2}}\]
D) \[285\text{ }c{{m}^{2}}\]
Correct Answer: C
Solution :
Let the length and breadth of rectangle be 7x and 5x respectively. Perimeter of rectangle = length of wire \[\therefore \] \[2(7x+5x)=72\Rightarrow 24x=72\Rightarrow x=3\] \[\therefore \] Length of rectangle \[=7\times 3=21\text{ }cm\] Breadth of rectangle \[=5\times 3=15\text{ }cm\] Area of rectangle \[=21\times 15=315\text{ }c{{m}^{2}}\]
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