| Column-I | Column-II |
| (i) Arun sells a car to his friend Amit at 10% loss. If Amit sells the car for Rs. 54000 and gains 20%, the original C.P. of the car (in Rs.) was | (p) 126 |
| (ii) A person borrowed Rs. 500 @ 3% per annum S.I. and Rs, 600 @ \[4\frac{1}{2}%\] per annum on the agreement for 3 years. The total S.I (in Rs.) that has to be ,.., paid is. | (q) 11200 |
| (iii) A certain amount was divided between A and B in the ratio\[4:3\]. If 8's share was Rs.4800, then the total amount (in Rs.) is |
A) (i)\[\to \](r); (ii)\[\to \](p); (iii) \[\to \](q)
B) (i)\[\to \](p); (ii)\[\to \](q); (iii)\[\to \](r)
C) (i)\[\to \](q); (ii)\[\to \](p); (iii) \[\to \](r)
D) (i)\[\to \](r); (ii)\[\to \](q); (iii)\[\to \](p)
Correct Answer: A
Solution :
(i) Let original C.P. of the car be Rs. x. Loss% = 10% C.P.\[=\frac{S.P.\times 100}{100-Loss%}\] \[\therefore \] C.P. for Arun, \[x=\frac{S.P.\times 100}{90}\] ?.(1) Now, S.P for Amit =Rs. 54000, Profit % = 20% \[\therefore \] \[C.P.=\left( \frac{S.P\times 100}{100+\text{Profit }\!\!%\!\!\text{ }} \right)\] C.P. for Amit \[=\frac{54000\times 100}{100+20}=\frac{54000\times 100}{120}\] =Rs. 45000 Now, cost price of car for Amit would be the selling price of car for Arun. \[\therefore \] S.P. for Arun = Rs.45000 From (1), we get. \[x=\frac{45000\times 100}{90}=50000\] Thus, original cost price of car =Rs. 50000. (ii) Case 1: Principal \[({{P}_{1}})\] =Rs. 500, Rate \[({{R}_{1}})=3%\] Case 2 Principal \[({{P}_{2}})=Rs.\,600,\] Rate \[({{R}_{2}})=4\frac{1}{2}%=\frac{9}{2}%\] Time = 3 years Case 1: S.I. \[=500\times \frac{3}{100}\times 3=Rs.\,45\] Case 2: S.I. \[=\frac{600\times 9\times 3}{2\times 100}=Rs.\,81\] Total S.I.=45+81 =Rs.126. (iii) Let amount of money A get be 4x and amount of money B get be 3x. According to question, B's share \[=Rs.4800\Rightarrow 3x=4800\] \[\Rightarrow \] \[x=\frac{4800}{3}=1600\] \[\therefore \]As share \[=4\times 1600=6400\] \[\therefore \]Total amount \[=4800+6400=Rs.1200\]
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