7th Class Mathematics Comparing Quantities Question Bank Comparing Quantities

  • question_answer
    The value of a machine depreciates every year by 10%. If the present value of the machine is Rs. 100000, what will be its value after three years.

    A)  20250                         

    B)  72900

    C)  90000            

    D)  81000

    Correct Answer: B

    Solution :

    (b) The value of the machine after depreciation of 10% per year for 3 years = \[Rs.\,\,100000\times \frac{90}{100}\times \frac{90}{100}\times \frac{90}{100}=72900/-\] Tip: \[9\times 9\times 9\]may be remembered as 729 It may also be remembered as, \[{{3}^{2}}\times {{3}^{2}}\times {{3}^{2}}={{3}^{6}}\] which is 729 (by doing so, you are also revising your concepts learnt in chapter - 6).


You need to login to perform this action.
You will be redirected in 3 sec spinner