A) \[2\frac{1}{3}%\]
B) \[4\frac{1}{3}%\]
C) \[6\frac{1}{3}%\]
D) \[3\frac{1}{3}%\]
Correct Answer: D
Solution :
(d): \[A=P+\frac{prt}{100}=12000\Rightarrow \frac{Prt}{100}=2000,where\,P=10000\] \[\therefore 12000=10000\left( 1+\frac{6r}{100} \right)\Rightarrow \frac{6}{5}=1+\frac{6r}{100}\] \[\Rightarrow \frac{1}{5}=\frac{6r}{100}\Rightarrow r=\frac{100}{30%}=3\frac{1}{3}%\]You need to login to perform this action.
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