A) \[{{[NiC{{l}_{4}}]}^{2-}}\]
B) \[{{[Co{{F}_{6}}]}^{3-}}\]
C) \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{2+}}\]
D) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]
Correct Answer: D
Solution :
Ni in presence of \[C{{N}^{-}}\] \[[N{{i}^{2+}}\]in presence of \[C{{N}^{-}}=[Ar]\]
As \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] has no unpaired electron. It is diamagnetic.
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