A) Colourless and diamagnetic
B) Coloured and octahedral
C) Colourless and paramagnetic
D) Coloured and paramagnetic
Correct Answer: A
Solution :
\[_{21}Sc=[Ar]\ 3{{d}^{1}}4{{s}^{2}}\] \[S{{c}^{3+}}=[Ar]\ 3{{d}^{0}}4{{s}^{0}}\] no unpaired electrons in d sub shell, so it is diamagnetic and colourless.
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