A) \[AgN{{O}_{3}}\]
B) \[ZnS{{O}_{4}}\]
C) \[FeS{{O}_{4}}\]
D) All of these
Correct Answer: A
Solution :
\[Cu+2AgN{{O}_{3}}\to 2Ag+Cu{{(N{{O}_{3}})}_{2}}\] \[Cu+ZnS{{O}_{4}}\to \]no reaction \[Cu+FeS{{O}_{4}}\to \]no reaction \[\left. \begin{matrix} {{E}^{0}}Z{{n}^{+2}}/Zn=-0.76\,V \\ {{E}^{0}}C{{u}^{2+}}/Cu=+0.34\,V \\ {{E}^{0}}F{{e}^{2+}}/Fe=-0.40\,V \\ {{E}^{0}}A{{g}^{+}}/Ag=+0.80\,V \\ \end{matrix} \right\}\] As it is clear that reduction potential of copper is more than Zn and Fe. Hence it is unable to displace them from their salts.
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