A) \[Ca\]
B) \[Fe\]
C) \[Cu\]
D) \[Li\]
Correct Answer: C
Solution :
\[Cu+{{H}_{2}}O\to \] No reaction \[E_{L{{i}^{+}}/Li}^{0}=-\,\,3.04\,\,V\] \[E_{{{H}^{+}}/{{H}_{2}}}^{0}=0.00\,V\] \[E_{C{{a}^{+}}/Ca}^{0}=-2.87\,V\] \[E_{C{{u}^{+}}/Cu}^{0}=+0.34\,V\] \[Cu\]comes below H in the electrochemical series. Hence, unable to displace hydrogen from water.
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