A) \[KI\]
B) \[NaBr\]
C) \[NaN{{O}_{3}}\]
D) \[{{K}_{2}}Cr{{O}_{4}}\]
Correct Answer: D
Solution :
\[2AgN{{O}_{3}}+{{K}_{2}}Cr{{O}_{4}}\to \underset{(\text{Red})}{\mathop{A{{g}_{2}}Cr{{O}_{4}}}}\,+2KN{{O}_{3}}\]
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