A) \[Ti{{O}_{2}}\]
B) \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\]
C) \[KMn{{O}_{4}}\]
D) \[ScC{{l}_{3}}\]
Correct Answer: B
Solution :
\[F{{e}^{+3}}-3{{d}^{5}}-5\] electrons unpaired. Fe will be attracted in magnetic field so will show increase in weight.
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