A) Cupric oxide is precipitated
B) Metallic copper is precipitated
C) Cuprous iodide is precipitated with liberation of iodine
D) No change occurs
Correct Answer: C
Solution :
Cuprous iodide is precipitated with liberation of iodine. \[2KI+CuS{{O}_{4}}\,\to \,Cu{{I}_{2}}+{{K}_{2}}S{{O}_{4}}+{{I}_{2}}\]
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