A) \[{{40}^{o}}C\]
B) \[-{{10}^{o}}C\]
C) \[{{10}^{o}}C\]
D) \[{{0}^{o}}C\]
Correct Answer: B
Solution :
\[\frac{{{\theta }_{1}}-{{\theta }_{2}}}{l}=80\Rightarrow \frac{30-{{\theta }_{2}}}{0.5}=80\Rightarrow {{\theta }_{2}}=-{{10}^{o}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
