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JEE Main & Advanced Physics Transmission of Heat Question Bank Conduction

  • question_answer
    The temperature of hot and cold end of a \[20cm\] long rod in thermal steady state are at \[{{100}^{o}}C\] and \[{{20}^{o}}C\] respectively. Temperature at the centre of the rod is      [MP PMT 1996]

    A)            \[{{50}^{o}}C\]                    

    B)            \[{{60}^{o}}C\]

    C)            \[{{40}^{o}}C\]                    

    D)            \[{{30}^{o}}C\]

    Correct Answer: B

    Solution :

               Temperature gradient \[=\frac{100-20}{20}=4{}^\circ C/cm\] temperature at centre \[=100-4\times 10\] = 60°C


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