A) \[3\times {{10}^{3}}J\]
B) \[6\times {{10}^{3}}J\]
C) \[9\times {{10}^{3}}J\]
D) \[12\times {{10}^{3}}J\]
Correct Answer: B
Solution :
\[\frac{Q}{t}=\frac{KA({{\theta }_{1}}-{{\theta }_{2}})}{l}=\frac{100\times 100\times {{10}^{-4}}(100-0)}{1}\] \[\Rightarrow \frac{Q}{t}=100\ Joule/sec=6\times {{10}^{3}}\ Joule/min\]
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