JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Conjugate, Modulus and Argument of complex number

  • question_answer
    \[(z+a)(\bar{z}+a)\], where \[a\] is real, is equivalent to

    A) \[|z-a|\]

    B) \[{{z}^{2}}+{{a}^{2}}\]

    C) \[|z+a{{|}^{2}}\]

    D) None of these

    Correct Answer: C

    Solution :

    As we know if a is real, then \[a=\overline{a}\] \ \[(z+a)(\overline{z}+a)=(z+a)(\overline{z}+\overline{a})=(z+a)(\overline{z+a})\] \[=|z+a{{|}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner