A) v in forward direction
B) 3v in forward direction
C) v in backward direction
D) 3v in backward direction
Correct Answer: B
Solution :
Let the initial mass of body = m Initial linear momentum = \[mv\] ?(i) When it breaks into equal masses then one of the fragment retrace back with same velocity \ Final linear momentum = \[\frac{m}{2}(-v)+\frac{m}{2}({{v}_{2}})\] ?(ii) By the conservation of linear momentum Þ \[mv=\frac{-mv}{2}+\frac{m{{v}_{2}}}{2}\]Þ \[{{v}_{2}}=3v\] i.e. other fragment moves with velocity 3v in forward directionYou need to login to perform this action.
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