A) 0.5 m/s
B) 0.25 m/s
C) 1 m/s
D) Data is insufficient
Correct Answer: A
Solution :
By the conservation of linear momentum \[{{m}_{B}}{{v}_{B}}={{m}_{a}}{{v}_{a}}\] Þ\[{{v}_{G}}=\frac{{{m}_{B}}\times {{v}_{B}}}{{{m}_{G}}}=\frac{5\times {{10}^{-3}}\times 500}{5}\]\[=0.5\ m/s\]
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