question_answer

Arrange the following steps of construction while dividing a line segment of length 8 cm internally in the ratio\[3:4\]. Steps of Construction

Step I: Draw a ray BY parallel to AX by making \[\angle ABY\]equal to \[\angle BAX\].

Step II: Join \[{{A}_{3}}{{B}_{4}}\]. Suppose it intersects AB at a point P. Then, P is the point dividing AB internally in the ratio \[3:4\].

Step III: Draw the line segment AB of length 8 cm.

Step IV: Mark of three point \[{{A}_{1}},{{A}_{2}},{{A}_{4}}\]on AX and 4 points \[{{B}_{1}},{{B}_{2}},{{B}_{3}},{{B}_{4}}\] on BY such that  \[A{{A}_{1}}={{A}_{1}}{{A}_{2}}={{A}_{2}}{{A}_{3}}=B{{B}_{1}}={{B}_{1}}{{B}_{2}}\]\[={{B}_{2}}{{B}_{3}}={{B}_{3}}{{B}_{4}}\].

Step V: Draw any ray AX making an acute angle\[~\angle BAX\] with AB.

A)  III, V, I, II. IV              

B)  III, IV. I, V, II

C)                     III, I, V, IV, II    

D)         III, V, I, IV, II