question_answer

Arrange the following steps of construction while constructing a triangle of scale \[AB=2.3\text{ }cm,\]\[BC=5\text{ }cm\] and \[AC=2.9\text{ }cm\]such that each of its sides is \[\frac{2}{3}rd\]of the corresponding side of the \[\Delta ABC\]. Steps of Construction

Step I: On BE, cut off 3 equal parts making \[{{B}_{1}},{{B}_{2}}\] and \[{{B}_{3}}\]

Step II: Now, draw C'A' parallel to CA. Then, \[\Delta A'BC'\] is the required A whose sides are of the corresponding sides of the \[\Delta ABC\].

Step III: From point B draw an arc of \[2.3\text{ }cm\]and from point C draw an arc of \[2.9\text{ }cm\]cutting each other at point A.

Step IV: Take\[BC=5\text{ }cm\].

Step V: Join \[{{B}_{3}}C\] and from \[{{B}_{2}}\] draw \[{{B}_{2}}C'\] parallel to \[{{B}_{3}}C,\] such that BC is 2/3 of BC.

Step VI: On B make an acute \[\angle CBE\]downwards.

Step VII: Join AB and AC. Then ABC is the required triangle.

A)     IV,     III,       VII,   I,     VI,    V,         II

B)     IV,     V,   I,     VI,   III,          VII,       II

C)     IV,     III,  VII,  VI,   I,            V,         II

D)     IV,    VII.  Ill,   VI,   V,      I,               II