A) \[LiCl<NaCl<BeC{{l}_{2}}\]
B) \[BeC{{l}_{2}}<NaCl<LiCl\]
C) \[NaCl<LiCl<BeC{{l}_{2}}\]
D) \[BeC{{l}_{2}}<LiCl<NaCl\]
Correct Answer: C
Solution :
Order of polarising power \[B{{e}^{++}}>L{{i}^{+}}>N{{a}^{+}}\] Hence order of covalent character \[BeC{{l}_{2}}>LiCl>NaCl\].
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