A) Ionic bond
B) Covalent bond
C) Co-ordinate
D) All of three
Correct Answer: B
Solution :
Electronic configuration of \[_{16}{{S}^{32}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{4}}\]. In the last orbit it has only 6 electron. So it require 2 electron to complete its octet, therefore it share 2 electron with two hydrogen atom and forms 2 covalent bond with it.
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