2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Carboxylic Acids

JEE Main & Advanced Chemistry Carboxylic Acids Question Bank Critical Thinking Carboxylic Acids

  • question_answer
    When \[C{{H}_{2}}=CH-COOH\] is reduced with \[LiAl{{H}_{4}}\], the compound obtained will be [AIEEE 2003]

    A)                 \[C{{H}_{3}}-C{{H}_{2}}-COOH\]               

    B)                 \[C{{H}_{2}}=CH-C{{H}_{2}}OH\]

    C)                 \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]

    D)                 \[C{{H}_{3}}-C{{H}_{2}}-CHO\]

    Correct Answer: B

    Solution :

               \[C{{H}_{2}}=CH-COOH\xrightarrow{LiAl{{H}_{4}}}\]\[C{{H}_{2}}=CH-C{{H}_{2}}OH+{{H}_{2}}O\]


You need to login to perform this action.
You will be redirected in 3 sec spinner