A) Cannizzaro reaction
B) Friedel-Craft's alkylation
C) Clemmensen reduction
D) Reimer-Tiemann reaction
Correct Answer: B
Solution :
New carbon-carbon bond formation take place in Friedel Craft?s alkylation and Reimer-Tiemann reaction. In Friedel Craft?s alkylation following mechanism involve \[R-Cl+AlC{{l}_{3}}\] ⇌ \[\underset{\text{Alkyl carbonium ion}}{\mathop{{{R}^{\oplus }}}}\,+AlCl_{4}^{}+HCl\]
Here new C-C bond formed between carbon of benzene ring and alkyl group. Similarly in Reimer-Tiemann reaction. 
Here new C-C bond formed between carbon of benzene ring and -CHO group.
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