JEE Main & Advanced Chemistry Nitrogen Containing Compounds Question Bank Critical Thinking Nitrogen

  • question_answer
    \[RN{{H}_{2}}\] reacts with \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl\] in aqueous \[KOH\] to give a clear solution. On acidification a precipitate is obtained which is due to the formation of [Roorkee 2000]

    A)                 \[R-\underset{H\,\,\,}{\overset{H\,\,}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,}{\mathop{{{N}^{+}}}}}\,}}}\,-S{{O}_{2}}{{C}_{6}}{{H}_{5}}O{{H}^{-}}\]

    B)                 \[R-{{N}^{-}}S{{O}_{2}}{{C}_{6}}{{H}_{5}}{{K}^{+}}\]

    C)                 \[R-NHS{{O}_{2}}{{C}_{6}}{{H}_{5}}\]

    D)                 \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}N{{H}_{2}}\]

    Correct Answer: C

    Solution :

               \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl+RN{{H}_{2}}\to RNHS{{O}_{2}}{{C}_{6}}{{H}_{5}}\xrightarrow{KOH}\]\[\underset{\text{soluble  in  }KOH}{\mathop{RNKS{{O}_{2}}{{C}_{6}}{{H}_{5}}}}\,\]


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