A) \[C{{H}_{3}}C{{H}_{2}}Cl\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[{{C}_{6}}{{H}_{6}}\]
D) \[{{C}_{3}}{{H}_{6}}\]
Correct Answer: D
Solution :
\[\underset{\text{Propene}}{\mathop{n\,C{{H}_{3}}-CH=C{{H}_{2}}}}\,\to \underset{\text{Polypropene}}{\mathop{{{\left( -C{{H}_{2}}-\underset{\,C{{H}_{3}}\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\, \right)}_{n}}}}\,\]
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