A) Are equal to each other in magnitude
B) Are not equal to each other in magnitude
C) Cannot be predicted
D) Are equal to each other
Correct Answer: A
Solution :
Let two vectors be \[\overrightarrow{A}\] and \[\overrightarrow{B}\] then \[(\overrightarrow{A}+\overrightarrow{B}).(\overrightarrow{A}-\overrightarrow{B})=0\] \[\overrightarrow{A}\ .\ \overrightarrow{A}-\overrightarrow{B}\ .\ \overrightarrow{B}+\overrightarrow{B}\ .\ \overrightarrow{A}-\overrightarrow{B}\ .\ \overrightarrow{B}=0\] \[{{A}^{2}}-{{B}^{2}}=0\]Þ\[{{A}^{2}}={{B}^{2}}\]\[\therefore \ \ A=B\]
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