A) \[1.5\times {{10}^{8}}m{{s}^{-1}}\]
B) \[2.1\times {{10}^{8}}m{{s}^{-1}}\]
C) \[2.6\times {{10}^{8}}m{{s}^{-1}}\]
D) \[5.2\times {{10}^{8}}m{{s}^{-1}}\]
Correct Answer: C
Solution :
\[T=\frac{{{T}_{0}}}{{{[1-({{v}^{2}}/{{c}^{2}})]}^{1/2}}}\] By substituting \[{{T}_{0}}=\]1 day and \[T=\]2 days we get \[v=2.6\times {{10}^{8}}\,m{{s}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
