A) 360
B) 300
C) 240
D) 120
Correct Answer: C
Solution :
The total number of words\[=\frac{6\ !}{2\ !}=360\]. The number of words in which BH come together are \[\frac{5\ !}{2\ !}\times 2\ !=120\]. Hence required number of ways in which \[B\] and \[H\] never came together are \[360-120=240\].You need to login to perform this action.
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