2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Solutions / विलयन

JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Critical Thinking Solutions

  • question_answer
    Vapour pressure of a solution of \[5g\] of non- electrolyte in \[100g\] of water at a particular temperature is \[2985\,N/{{m}^{2}}\]. The vapour pressure of pure water is \[3000N/{{m}^{2}}\]. The molecular weight of the solute is             [IIT Screening 1993]

    A)                 60          

    B)                 120

    C)                 180        

    D)                 380

    Correct Answer: C

    Solution :

                \[\frac{{{P}^{o}}-{{P}_{s}}}{{{P}^{o}}}=\frac{\frac{{{W}_{2}}}{{{M}_{2}}}}{\frac{{{W}_{1}}}{{{M}_{1}}}}\] = \[\frac{3000-2985}{3000}=\frac{\frac{5}{{{M}_{2}}}}{\frac{100}{18}}\text{ or }{{M}_{2}}=180\]


You need to login to perform this action.
You will be redirected in 3 sec spinner