A) \[2.5\times {{10}^{30}}atoms/c{{m}^{3}}\]
B) \[1.0\times {{10}^{13}}atoms/c{{m}^{3}}\]
C) \[1.0\times {{10}^{15}}atoms/c{{m}^{3}}\]
D) \[2.5\times {{10}^{36}}atoms/c{{m}^{3}}\]
Correct Answer: C
Solution :
Number density of atoms in silicon specimen = 5 ´ 1028 atom/m3 = 5 ´ 1022 atom/cm3 Since one atom of indium is doped in 5 ´ 107 Si atom. So number of indium atoms doped per cm3 of silicon. \[n=\frac{5\times {{10}^{22}}}{5\times {{10}^{7}}}=1\times {{10}^{15}}\,atom/c{{m}^{3}}.\]You need to login to perform this action.
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