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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Critical Thinking Coordination

  • question_answer
    The coordination number and oxidation state of \[Cr\] in \[{{K}_{3}}\left[ Cr{{\left( {{C}_{2}}{{O}_{4}} \right)}_{3}} \right]\] are, respectively [CBSE PMT 1995]

    A) 4 and +2

    B) 6 and +3

    C) 3 and +3

    D) 3 and 0

    Correct Answer: B

    Solution :

    Its coordination number will be 6 because it is bonded with three bidentale ligands. Oxi. No. of \[Cr\] in \[\underset{-1}{\mathop{{{K}_{3}}}}\,[Cr\underset{-2}{\mathop{{{({{C}_{2}}{{O}_{4}})}_{3}}}}\,]\] is \[x+3(-2)+3(+1)=0\] \[\Rightarrow \,\,x=+3\]


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