A) Reflexive and symmetric
B) Transitive and symmetric
C) Equivalence
D) Reflexive, transitive but not symmetric
Correct Answer: D
Solution :
Since n | n for all \[n\in N\], therefore R is reflexive. Since 2 | 6 but \[6\not{|}2\], therefore R is not symmetric. Let n R m and m R p Þ n|m and m|p Þ n|p Þ nRp. So, R is transitive.
You need to login to perform this action.
You will be redirected in
3 sec
