A) N-type and its resistivity is 0.34 ohm-metre
B) P-type and its resistivity is 0.034 ohm-metre
C) N-type and its resistivity is 0.034 ohm-metre
D) P-type and its resistivity is 3.40 ohm-metre
Correct Answer: A
Solution :
\[{{n}_{e}}=8\times {{10}^{18}}/{{m}^{3}},\ \ {{n}_{h}}=5\times {{10}^{18}}/{{m}^{3}}\] \[{{\mu }_{e}}=2.3\frac{{{m}^{2}}}{volt-\sec },\ \ {{\mu }_{h}}=0.01\frac{{{m}^{2}}}{volt-\sec }\] \[\because {{n}_{e}}>{{n}_{h}}\] so semiconductor is N-type Also conductivity \[\sigma =\frac{1}{\text{Resistivity}\,(\rho )}=e({{n}_{e}}{{\mu }_{e}}+{{n}_{h}}{{\mu }_{h}})\] Þ\[\frac{1}{\rho }=1.6\times {{10}^{-19}}[8\times {{10}^{18}}\times 2.3+5\times {{10}^{18}}\times 0.01]\] Þ r = 0.34 W-m.
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