JEE Main & Advanced Chemistry GOC Question Bank Critical Thinking

  • question_answer The number of possible isomers for compound \[{{C}_{2}}{{H}_{3}}C{{l}_{2}}Br\] is [MP PMT 1999]

    A) 2

    B) 3

    C) 4

    D) 5

    Correct Answer: B

    Solution :

      \[{{C}_{2}}{{H}_{3}}C{{l}_{2}}Br\] Three isomers are possible \[C{{H}_{3}}-C\,<-\begin{matrix}    Cl  \\    Cl  \\    Br  \\ \end{matrix}\]      1-bromo-1, 1-dichloroethane \[Br-C{{H}_{2}}\,-CH<\begin{matrix}    Cl  \\    {}  \\    Br  \\ \end{matrix}\]1-bromo-2, 2-di-chloroethane \[Cl-C{{H}_{2}}\,-CH<\begin{matrix}    Br  \\    {}  \\    Cl  \\ \end{matrix}\]1-bromo-1, 2-dichloroethane

adversite


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