• # question_answer A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying odd places, then the common ratio will be equal to A) 2 B) 3 C) 4 D) 5

Let there be $2n$ terms in the given G.P. with first term $a$and the common ratio$r$. Then, $a\frac{({{r}^{2n}}-1)}{(r-1)}=5a\frac{({{r}^{2n}}-1)}{({{r}^{2}}-1)}$$\Rightarrow$$r+1=5$$\Rightarrow$$r=4$.