A) Reflexive
B) Symmetric
C) Transitive
D) None of these
Correct Answer: D
Solution :
On the set N of natural numbers, \[R=\{(x,y):x,y\in N,2x+y=41\}\]. Since \[(1,1)\notin R\]as \[2.1+1=3\ne 41\]. So, R is not reflexive. \[(1,\,39)\in R\]but \[(39,\,1)\notin R\]. So R is not symmetric (20, 1) (1, 39 \[\in R\]. But \[(20,39)\notin R\], So R is not transitive.
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