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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Critical Thinking Solutions

  • question_answer
    \[{{K}_{f}}\] of 1,4-dioxane is 4.9 \[mo{{l}^{-1}}\] for 1000 g. The depression in freezing point for a 0.001 m  solution in dioxane is  [DPMT 2001]

    A)                 0.0049  

    B)                 4.9 + 0.001

    C)                 4.9         

    D)                 0.49

    Correct Answer: A

    Solution :

                \[\Delta T={{K}_{f}}\times \text{Molality}\]\[=4.9\times 0.001=0.0049K\]


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