A) Large amount of\[C{{O}_{2}}\], no water and no energy
B) 132 gms of\[C{{O}_{2}}\], 54 gms of water and 337 kcals of energy
C) 264 gms of\[C{{O}_{2}}\], 108 gms of water and 674 kcals of energy
D) 528 gms of \[C{{O}_{2}}\], 216 gms of water and 1348 kcals of energy
Correct Answer: C
Solution :
Reaction of respiration is \[{{C}_{6}}{{H}_{12}}{{O}_{6}}_{{}}~+\text{ }6{{O}_{2}}_{{}}~6C{{O}_{2}}_{{}}+\text{ }6{{H}_{2}}O+\text{ }674kcal\] In this reaction considering molecular weight of each element, we get \[{{C}_{6}}{{H}_{12}}{{O}_{6}}_{{}}~=\text{ }6\text{ }times\text{ }12\text{ }+12\text{ }times\text{ }1\text{ }+\text{ }6\text{ }times\text{ }16\text{ }=\text{ }180gm\] \[{{O}_{2}}_{{}}~=\text{ }6\text{ }times\text{ }32\text{ }=\text{ }192gm\] Now we consider products of this reaction i.e. \[6C{{O}_{2}}\]and\[6{{H}_{2}}O\] \[6C{{O}_{2}}_{{}}~=\text{ }6\text{ }\left( 12\text{ }+\text{ }32 \right)\text{ }=\text{ }264gm\] \[6{{H}_{2}}O=\text{ }6\text{ }\left( 2\text{ }+\text{ }16 \right)\text{ }=\text{ }108gm\]
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