A) \[{{H}_{2}}C=C{{H}_{2}}\to C{{H}_{3}}C{{H}_{2}}Cl\]
B) \[{{H}_{3}}C-O-C{{H}_{3}}\to C{{H}_{3}}Cl\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\to C{{H}_{3}}C{{H}_{2}}Cl\]
D) \[HC\equiv CH\to C{{H}_{2}}=CHCl\]
Correct Answer: B
Solution :
\[C{{H}_{3}}-O-C{{H}_{3}}+PC{{l}_{5}}\to 2C{{H}_{3}}Cl+POC{{l}_{3}}\] \[C{{H}_{3}}C{{H}_{2}}OH+PC{{l}_{5}}\to C{{H}_{3}}C{{H}_{2}}Cl+HCl+POC{{l}_{3}}\] So, both reaction carried out by \[PC{{l}_{5}}\]
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