JEE Main & Advanced Physics Wave Mechanics Question Bank Critical Thinking

  • question_answer
    An observer moves towards a stationary source of sound with a speed 1/5th of the speed of sound. The wavelength and frequency of the source emitted are \[\lambda \] and \[f\] respectively. The apparent frequency and wavelength recorded by the observer are respectively  [CBSE PMT 2003]

    A)            \[1.2\ f,\ \lambda \]          

    B)            \[f,\ 1.2\lambda \]

    C)            \[0.8f,\ 0.8\lambda \]       

    D)            \[1.2f,\ 1.2\lambda \]

    Correct Answer: A

    Solution :

               \[n'=\frac{v+{{v}_{0}}}{v}.n=\frac{v+\frac{v}{5}}{v}.f=\frac{6}{5}f=1.2f\] and since the source is stationary, so wave length remains unchanged for observer.


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