JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
    A transistor is used as an amplifier in CB mode with a load resistance of 5 k W the current gain of amplifier is 0.98 and the input resistance is 70 W, the voltage gain and power gain respectively are                                             [Pb. PET 2003]

    A)            70, 68.6                                   

    B)            80, 75.6

    C)            60, 66.6                                   

    D)            90, 96.6

    Correct Answer: A

    Solution :

                       In common base mode a = 0.98, R = 5 kW, Rin = 70W \ voltage gain \[{{A}_{v}}=\alpha \times \frac{R}{{{R}_{in}}}=0.98\times \frac{5\times {{10}^{3}}}{70}=70\] Power gain = Current gain ´ Voltage gain                   = 0.98 ´ 70 = 68.6


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