• # question_answer If a root of the given equation $a(b-c){{x}^{2}}+b(c-a)x+c(a-b)=0$is 1, then the other will be    [RPET 1986] A) $\frac{a(b-c)}{b(c-a)}$ B) $\frac{b(c-a)}{a(b-c)}$ C) $\frac{c(a-b)}{a(b-c)}$ D) None of these

Let $\alpha =1$ and the other root is$\beta$, then product of roots 1. $\beta =\frac{c(a-b)}{a(b-c)}\Rightarrow \beta =\frac{c(a-b)}{a(b-c)}$