A) 0.0001%
B) 0.01%
C) 0.1%
D) 0.15%
Correct Answer: B
Solution :
\[{{X}^{-}}+{{H}_{2}}O\]⇌ \[HX+O{{H}^{-}}\] \[{{K}_{h}}=\frac{{{10}^{-14}}}{{{10}^{-5}}}\] so \[h=\sqrt{\frac{{{10}^{-9}}}{{{10}^{-1}}}}={{10}^{-4}}\] \[100\times {{10}^{-4}}={{10}^{-2}}\] So, 0.01%.You need to login to perform this action.
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