A) \[1.8\times {{10}^{-7}}%\]
B) \[0.8\times {{10}^{-9}}%\]
C) \[3.6\times {{10}^{-7}}%\]
D) \[3.6\times {{10}^{-9}}%\]
Correct Answer: A
Solution :
1 litre of water contains 1000/18 mole. So degree of ionization \[=\frac{{{10}^{-7}}\times 18}{1000}=1.8\times {{10}^{-7}}\]%.You need to login to perform this action.
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